A and B are two candidates for seeking admission in IIT. The probability that A is selected is 0.4 and the probability that both A and B are selected is at the most 0.2. Then P(B) is less than:
A
0.9
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B
0.7
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C
0.8
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D
None
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Solution
The correct option is C 0.8 Given: P(A)=0.4,P(A∩B)≤0.2.P(A∪B)≤1⇒P(A)+P(B)−P(A∩B)≤1⇒P(B)≤1−0.4+P(A∩B)≤0.6+0.2=0.8.