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Question

A and B are two candidates seeking admission in I.I.T. The probability that A is selected is 0.5 and the probability that both A and B are selected is at most 0.3. Is it posssible that the probability of B getting selected is 0.9?

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Solution

Let A denote the event that the candidate A is selected and B the event that B is selected.
It is given that P(A)=0.5 ...(1)
P(AB)=0.3 ...(2)

Now P(A)+P(B)P(AB)=P(AB)1
0.5+P(B)P(AB)1, by 1
P(B)0.5+P(AB)0.5+0.3, by 2
P(B)0.8
Hence, P(B)=0.9 is not possible.

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