A and B are two candidates seeking admission in I.I.T. The probability that A is selected is 0.5 and the probability that both A and B are selected is at most 0.3. Is it posssible that the probability of B getting selected is 0.9?
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Solution
Let A denote the event that the candidate A is selected and B the event that B is selected. It is given that P(A)=0.5 ...(1) P(A∩B)≤=0.3 ...(2)
Now P(A)+P(B)−P(A∩B)=P(A∪B)≤1 ⇒0.5+P(B)−P(A∩B)≤1, by 1 ⇒P(B)≤0.5+P(A∩B)≤0.5+0.3, by 2 ⇒P(B)≤0.8