A and B are two events such that P A-B -5-6-P AB -1-3-P B -1-2- then the event A and B are

The correct option is A independentP(A+B) = P(A) + P(B) P(AB) nbsp;5/6 = 1/2 + P(A) 1/3P(A) = 2/3Therefore P(A)*P(B) = P(AB)Hence A and B are independent ...

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Standard X

Mathematics

Probability

A and B are t...

Question

A and B are two events such that $P (A + B) = \frac{5}{6}, P (A B) = \frac{1}{3}, P (B) = \frac{1}{2},$ then the event A and B are

independent

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M.E

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Solution

The correct option is A independent
P(A+B) = P(A) + P(B) - P(AB)
5/6 = 1/2 + P(A) -1/3
P(A) = 2/3
Therefore P(A)*P(B) = P(AB)
Hence A and B are independent

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A and B are two events such that P(A+B)=56,P(AB)=13,P(B)=12, then the event A and B are

The correct option is A independentP(A+B) = P(A) + P(B) - P(AB) 5/6 = 1/2 + P(A) -1/3P(A) = 2/3Therefore P(A)*P(B) = P(AB)Hence A and B are independent

A and B are two events such that $P (A + B) = \frac{5}{6}, P (A B) = \frac{1}{3}, P (B) = \frac{1}{2},$ then the event A and B are

The correct option is A independent
P(A+B) = P(A) + P(B) - P(AB)
5/6 = 1/2 + P(A) -1/3
P(A) = 2/3
Therefore P(A)*P(B) = P(AB)
Hence A and B are independent