It is given that A and B be any events such that,
P( A )≠0
(i)
It is given that A is a subset of B then,
A∩B=A P( A∩B )=P( B∩A )=P( A )
The probability P( B|A ) is calculated as,
P( B|A )= P( A∩B ) P( A ) P( B|A )= P( A ) P( A ) =1
Therefore, the value of P( B|A ) is 1.
(ii)
It is given that,
A∩B=ϕ
So,
P( A∩B )=0
P( B|A )= P( A∩B ) P( A ) P( B|A )= 0 P( A ) =0
Therefore, the value of P( B|A ) is 0.
If A and B are two events such that P (A) ≠ 0 and P(B|A) = 1, then.
(A) A ⊂ B
(B) B ⊂ A
(C) B = Φ
(D) A = Φ