Question

$AandB$ are two events such that $P\left(A\right)=0.8,P\left(B\right)=0.6,andP(A\cap B)=0.5$, then the value of $P\left(\frac{A}{B}\right)$ is

• A. $\frac{5}{6}$
• B. $\frac{5}{8}$
• C. $\frac{9}{10}$
• D. None of these

Answer 1

The correct option is A

$\frac{5}{6}$

Explanation for correct option:

Conditional probability:

Given that, $P\left(A\right)=0.8,P\left(B\right)=0.6,andP(A\cap B)=0.5$

$\mathbf{P}\left(\frac{A}{B}\right)\mathbf{}\mathbf{=}\frac{\mathbf{P}\mathbf{(}\mathbf{A}\mathbf{\cap }\mathbf{B}\mathbf{)}}{\mathbf{P}\mathbf{\left(}\mathbf{B}\mathbf{\right)}}$

$=\frac{0.5}{0.6}$

$=\frac{5}{6}$

Hence, Option(A) is correct