Question

A and B are two gases. A is identified with the glass rod dipped in $N{H}_3$ and $B$ is identified with the glass rod dipped in $HCl$. Then A and B are :

• A. $HCl,N{O}_2$
• B. $HCl,N{H}_3$
• C. $N{H}_3$, H$Cl$
• D. $N{H}_3,S{O}_2$

Answer 1

The correct option is B $HCl,N{H}_3$

When glass rod dipped in $N{H}_3$, it is $HCl$ which reacts to form $N{H}_{4}Cl$ and when dipped in $HCl$, it is $N{H}_3$ which react to form $N{H}_{4}Cl$.