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Maxwell's Distribution of Speeds

A and B are t...

Question

A and B are two gases. $\frac{T_{A}}{M_{A}} = 4 \frac{T_{B}}{M_{B}}$ where T is the temperature and M is the molecular mass. If $C_{A}$ and $C_{B}$ are rms speeds, then $\frac{C_{A}}{C_{B}}$ will be

A

2

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B

4

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C

0.5

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D

0.25

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Solution

The correct option is A 2
$\frac{C_{A}}{C_{B}} = \frac{\sqrt{\frac{3 R T_{A}}{M_{A}}}}{\sqrt{\frac{3 R T_{B}}{M_{B}}}} = 2$

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