wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A and B are two hollow metal spheres of radii 50cm and 1m carrying charges 0.6μC and 1μC respectively. They are connected externally by a conducting wire. Now the charge flows from :

A
A to B till the charges become equal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
A to B till the potentials become equal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
B to A till the charges become equal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
B to A till the potentials become equal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C A to B till the potentials become equal
The potential of a sphere of radius r carrying a charge q is kqr.
Hence potential of first sphere=VA=k(0.6μC)0.5m
Potential of second sphere=VB=k(1μC)1m
VA>VB
Hence charge flows from A to B till the potentials become equal.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Net Flow of Charge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon