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Question

A and B are two identical rods of internal resistance r=1Ω. If R=2Ω,VA=4m/s,VB=3m/s, length of rods is 1 m, then current in R is (Magnetic field is 2T)

A
1A
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B
0.4A
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C
0.6A
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D
0.8A
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Solution

The correct option is B 0.4A

The voltage in induced in the left rod is BVL=2×4×1=8V. The bottom part of the rod is at higher potential.

The voltage in induced in the rightside rod is BVL=2×3×1=6V. The top part of the rod is at higher potential.

By K.V.L,
8=i+2i1 ...(1)
6=(1i1)2i1
6=i3i1 ...(2)
By (1) & (2)
i1=0.4 A

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