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Question

A and B are two metals with threshold frequencies 1.8×1014Hz and 2.2×1014Hz. Two identical photons of energy 0.825eV each are incident on them. Then photoelectrons are emitted in (Take h=6.6×1034Js)

A
B alone
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B
A alone
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C
Neither A nor B
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D
Both A and B
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Solution

The correct option is B A alone
Given- ν0A=1.8×1014Hz,ν0B=2.2×1014Hz,E=0.825eV=0.825×1.6×1019J ,
Frequency of incident photon ,
E=hν ,

or ν=E/h=0.825×1.6×10196.6×1034=2×1014Hz ,

The photoelectrons will be emitted from the metal surface , if frequency of incident photon is greater than threshold frequency .
As ν>ν0A and ν<ν0B ,
Therefore, photoelectrons will be emitted from A alone .

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