Question

A and B are two objects. The temperature of A is greater than that of B. This means that.

• A. The molecules of A move faster on an average than the molecules of B
• B. The total energy of A is greater than the total energy of the molecules of B
• C. The average potential energy of A is greater than the average potential energy of B
• D. The heat content of A will always be greater than that of B

Answer 1

Answer: (A)

The molecules of A move faster on an average than the molecules of B

From the equipartition theorem, the kinetic energy of a molecular system depends upon temperature as

$\Rightarrow KE=\frac{3}{2}{K}_{B}T$

i.e, directly proportional so, if temperature of $A$ is greater than that of $B$ then $KE$ of $A$ will be greater than $KE$ of $B.$

Hence, the answer is the molecules of $A$ move faster on an average than the molecules of $B.$