A and B are two points on one bank of a straight river, C and D are two points on the other bank. The direction from C to D is the same as from A to B. If AB = a, ∠CAD=α, ∠DAB=β, ∠CBA=γ prove that CD=asinαsinγsinβ.sin(α+β+γ)
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Solution
We have marked the angles as given ∠ACB=180o−(α−β)−γ=180o−(α+β+γ) sinACB=sin(α+β+γ) ...(1) Using sine formula on ΔABC ABsinACB=ACsinγ ∴AC=asinγsin(α+β+γ), by (1) ...(2) Again from ΔACD by sine formula, we have CDsinα=ACsinβ ∴CD=sinαsinβ.asinγsin(α+β+γ) by (2) =asinαsinγsinβsin(α+β+γ)