CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A and B are two points on the axis and the perpendicular bisector respectively of a electric dipole. A and B are far away from the dipole and at equal distance from it. The field at A and B are :

A
EA=EB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
EA=2EB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
EA=2EB
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
|EB|=12|EA|,andEBisperpendiculartoEA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C EA=2EB
The electric field intensity due to the dipole at the point A on the axis of the dipole is given by
EA=2kpr3......(1)
where, p is electric dipole moment, r is the distance of point A from dipole and k=14πϵ0
The direction of the electric field E is along the axis of the dipole from the negative charge towards the positive charge.
Also,
The electric field intensity due to the dipole at the point B on the perpendicular bisector of the dipole is given by
EB=kpr3......(2)
The direction of the electric field E is parallel to the axis of the dipole from the positive charge towards the negative charge.
Hence, direction of
electric field intensity due to the dipole at the point A is opposite to that of at point B.(refer the figure)
From (1) and (2), we get
EA=2EB
133280_125093_ans.png

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Potential Due to a Point Charge and System of Charges
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon