A and B are two stations 300 km apart. Two trains start simultaneously from A and B, each to the opposite stations. The train from A reaches B in 9 hours, the train from B reaches A in four hours after they meet. Find the speed of each train.

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Solution

$D = v \times t$
$D = 300 k m$ .
$v_{1} \times g = 300$
$v_{1} = \frac{100}{3} K m / h$ .
$v_{2} .4 = 300$
$v_{2} = 75 k m / h$

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A and B are two stations 300 km apart. Two trains start simultaneously from A and B, each to the opposite stations. The train from A reaches B in 9 hours, the train from B reaches A in four hours after they meet. Find the speed of each train.

D=v×tD=300 km.v1×g=300v1=1003 Km/h.v2.4=300v2=75 km/h

$D = v \times t$
$D = 300 k m$ .
$v_{1} \times g = 300$
$v_{1} = \frac{100}{3} K m / h$ .
$v_{2} .4 = 300$
$v_{2} = 75 k m / h$