A and B can do a job together in 7 days. A is 134 times as efficient as B. The same job can be done by A alone in how many days?
11 days
(A’s 1 day’s work): (B’s 1 day’s work) be 7x and 4x respectively.
Let A’s and B’s 1 day’s work be 7x and 4x respectively.
Then,
7x+4x=17⇒11x=17⇒x=177
∴ A’s 1 day’s work =
(177×7)=111
So, A will complete the work in 11 days.