Question

$A$ and $B$ can do a piece of work in $15$ days and $18$ days respectively. A worked at it for $10$ days and then $B$ finished the remaining work. Find the time taken by $B$ to finish the remaining work.

Answer 1

Let the amount of work be $x$

$A,B$ can do the work in $15,18$ days respectively

$⟹$ the amount of work $A,B$ can do in one day is $\frac{x}{15},\frac{x}{18}$ respectively

Let the time taken is $m$

From the given conditions ,

$\frac{10x}{15}+\frac{mx}{18}=x⟹m=6$ days