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Byju's Answer

Standard VII

Mathematics

Time and Work

A and B can d...

Question

A and B can do a work in $8$ days , B and C in $12$ days, and A and C in $16$ days. In how many days can they complete the work, all working together ?

4 \frac{2}{17}

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7 \frac{5}{13}

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6 \frac{9}{6}

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4 \frac{8}{13}

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Solution

The correct option is C $7 \frac{5}{13}$
2( A+B +C ) one day work $= \frac{1}{8} + \frac{1}{12} + \frac{1}{16} = \frac{13}{48}$

Then (A+B+C ) one day work $= \frac{13}{48} \times \frac{1}{2} = \frac{13}{96}$

So (A+B+C) done work $= \frac{96}{13} = 7 \frac{5}{13}$ days

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A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in how many days?

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A and B can do a work in 8 days , B and C in 12 days, and A and C in 16 days. In how many days can they complete the work, all working together ?

The correct option is C 75132( A+B +C ) one day work =18+112+116=1348Then (A+B+C ) one day work =1348×12=1396So (A+B+C) done work =9613=7513 days

A and B can do a work in $8$ days , B and C in $12$ days, and A and C in $16$ days. In how many days can they complete the work, all working together ?

The correct option is C $7 \frac{5}{13}$
2( A+B +C ) one day work $= \frac{1}{8} + \frac{1}{12} + \frac{1}{16} = \frac{13}{48}$

Then (A+B+C ) one day work $= \frac{13}{48} \times \frac{1}{2} = \frac{13}{96}$

So (A+B+C) done work $= \frac{96}{13} = 7 \frac{5}{13}$ days