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Question

A and B can separately do a piece of work in 20 and 15 days respectively. They worked together for 6 days after which B was replaced by C. If the work was finished in next 4 days, then the number of days in which C alone could do the work will be

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Solution

(A + B)'s 6 day's work = 6(120+115)=710
(A + C)'s 4 day's work = 310;
(A + C)'s 1 day's work = 340
A's 1 day's work = 120
C's day's work = (340120)=140
Hence C alone can finish the work in 40 days

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