A and B have 460coins altogether- If 3-4 of A-s number of coins is equal to 2-5 of B-s number of coins- find how many coins must B give to A so that they both have equal number of coins-

The correct option is A 70 Let A's coins be x B's coins = 460 x 3 4 x = 2 5 (460 x) 15x = 8(460 x) 15x = 3680 8x 23x ...

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Byju's Answer

Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

A and B have ...

Question

A and B have $460$ coins altogether. If $\frac{3}{4}$ of A's number of coins is equal to $\frac{2}{5}$ of B's number of coins. find how many coins must B give to A so that they both have equal number of coins.

70

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Solution

The correct option is A $70$
Let A's coins be $x$
B's coins $= 460 - x$
$\frac{3}{4} x = \frac{2}{5} (460 - x) 15 x = 8 (460 - x) 15 x = 3680 - 8 x 23 x = 3680 x = 160$
A's coins $= 160$
B's coins $= 300$
So B has to give $A (140 \div 2) = 70$ coins

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A and B have 460coins altogether. If 34 of A's number of coins is equal to 25 of B's number of coins. find how many coins must B give to A so that they both have equal number of coins.

The correct option is A 70Let A's coins be xB's coins =460−x34x=25(460−x)15x=8(460−x)15x=3680−8x23x=3680x=160A's coins =160B's coins =300So B has to give A(140÷2)=70 coins

A and B have $460$ coins altogether. If $\frac{3}{4}$ of A's number of coins is equal to $\frac{2}{5}$ of B's number of coins. find how many coins must B give to A so that they both have equal number of coins.

The correct option is A $70$
Let A's coins be $x$
B's coins $= 460 - x$
$\frac{3}{4} x = \frac{2}{5} (460 - x) 15 x = 8 (460 - x) 15 x = 3680 - 8 x 23 x = 3680 x = 160$
A's coins $= 160$
B's coins $= 300$
So B has to give $A (140 \div 2) = 70$ coins