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Question

A and B participate in a race with acceleration a1 and a2 respectively. A reaches t times earlier than B at finish line and there velocities at finish line are v1 and v2 respectively. If difference between their velocities is v then find the value of v

A
a1+a22
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B
a1a2t
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C
a1a2a1+a2t
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D
2a1a2a1+a2t
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Solution

The correct option is B a1a2t
s=12 a1 t20=12a2(t0+t)2

a1a2×2s=v

(1a21a1)×2s=t

=2s=a1a2ta1a2

va1a2=a1a2ta1a2

v=a1a2t

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