CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A and B throw a pair of dice alternately, till one of them gets a total of 10 and wins the game. Find their respective probabilities of winning, if A starts first.


Solution

Here, two persons are A & B and A is the first person to throw the pair of dice. Probability of getting a total of 10 in a throw of a pair of dice is success.

Now, probability of getting a total of 10 is:
P(total of 10) =(4,6),(6,4),(5,5)36=336=112

P (not getting a total of 10)=1112=1112

P(A wins) =112+(1112)2(112)+(1112)4(112)...to 

=112[1+(1112)2+(1112)4+...to ]

=11211(1112)2[for an infinite G.P.sum=first term1r]

=112[123144]=112×14423=1223

P(B wins)= 1-P(A wins)

=11223

=1123

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More



footer-image