$A$ can finish a piece of work in $15$ days and $B$ can do it in $10$ days. They worked together for $2$ days and then $B$ goes away. In how many days will $A$ finish the remaining work?

A can finish a work in 36 months, B in 18 months and C in 24 months. B and C start the work but are forced to leave after 4 months. The remaining work was done by A in:

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A and B together finish a work in 15 months. They worked together for 10 months and then B left. After another 12 months, A finished the remaining work. In how many months A alone can finish the job?

The correct option is D 36 (A + B)'s 10 month's work = (115 × 10) = 23 Remaining work = (1 − 23) = 13 Now, 13 work is done by A in 12 months Whole work will be done by A in (12 × 3) = 36 months

The correct option is D
36

(A + B)'s 10 month's work = $(\frac{1}{15} \times 10) = \frac{2}{3}$
Remaining work = $(1 - \frac{2}{3}) = \frac{1}{3}$

Now, $\frac{1}{3}$ work is done by A in $12 m o n t h s$

Whole work will be done by A in $(12 \times 3) = 36 m o n t h s$