A and B working together can do a piece of work in 10 days. B alone can do the same work in 15 days. How long will A along take to do the same work?

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Solution

It is given that

A and B work together to do a piece of work in 10 days

B alone can do the same work in 15 days

So we get

A and B one day work = $\frac{1}{10}$

B’s one day work = $\frac{1}{15}$

A’s one day work = $\frac{1}{10}$ – $\frac{1}{15}$

Taking LCM

= $\frac{(3 - 2)}{30}$

= $\frac{1}{30}$

No. of days A can do the same work = 30 days

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A and B working together can do a piece of work in 10 days. B alone can do the same work in 15 days. How long will A along take to do the same work?

It is given that A and B work together to do a piece of work in 10 days B alone can do the same work in 15 days So we get A and B one day work = 110 B’s one day work = 115 A’s one day work = 110 – 115 Taking LCM = (3−2)30 = 130 No. of days A can do the same work = 30 days