A and B. working together can finish a piece of work in 6 days, while A alone can do it in 9 days. How much lime will B alone take to finish it?

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Solution

Given,
A and B both's one day's work $= \frac{1}{6}$

A's alone's one day's work $= \frac{1}{9}$

$∴$ B's alone one day's work \\ $= \frac{1}{6} - \frac{1}{9}$

$= \frac{3 - 2}{18} = \frac{1}{18}$

$∴$ B can finish the work in 18 days

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A and B. working together can finish a piece of work in 6 days, while A alone can do it in 9 days. How much lime will B alone take to finish it?

Given,A and B both's one day's work =16 A's alone's one day's work =19 ∴ B's alone one day's work \\=16−19 =3−218=118 ∴ B can finish the work in 18 days

Given,
A and B both's one day's work $= \frac{1}{6}$

A's alone's one day's work $= \frac{1}{9}$

$∴$ B's alone one day's work \\ $= \frac{1}{6} - \frac{1}{9}$

$= \frac{3 - 2}{18} = \frac{1}{18}$

$∴$ B can finish the work in 18 days