Question

A atomic power reactor furnace can deliver 300 MW. The energy released due to fission of each of uranium atom $U^{238}$ is 170 MeV. The number of uranium atoms fission per hour will be

• A. $5\times {10}^{15}$
• B. $10\times {10}^{22}$
• C. $40\times {10}^{21}$
• D. $30\times {10}^{25}$

Answer 1

The correct option is C $40\times {10}^{21}$

By using $P=\frac{W}{t}=\frac{n\times E}{t}$ where n = Number of uranium atom fission and E = Energy released due to each fission so $300\times {10}^6=\frac{n\times 170\times {10}^6\times 1.6\times {10}^{-19}}{3600}\Rightarrow n=40\times {10}^{21}$