Given,
a +b = 10
a² + b² = 58
We know that,
(a+b)² = a² +b² +2ab
10² = 58 +2ab
100 = 58 + 2ab
2ab = 42
ab = 21
Again,
(a+b)³ = a³ +b³ + 3ab(a+b)
10³ = a³ +b³ + 3*21(10)
10³ = a³ + b³ +630
1000 - 630 = a³ +b³
a³ + b³ = 370
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