(a + b) (2a – 3b + c) – (2a – 3b) c = 2a2 – 2b2 – ab + 4bc – 2ac.
True
False
(a + b) (2a – 3b + c) – (2a – 3b) c
(2a2 - 3ab + ac + 2ab - 3b2 + bc) - (2ac - 3bc)
⇒ 2a2 - 3ab + ac + 2ab - 3b2 + bc - 2ac + 3bc.
⇒ 2a2 - ab - ac - 3b2 + 4bc.
Simplify: (a+b)(2a−3b+c)−(2a−3b)(c). [3 MARKS]
Reduce 2a2 − 2ac + 3ab − 3bc3a2 − 3ac − 2ab + 2bc
Simplify (a+b)(2a−3b+c)−(2a−3b)c. [3 MARKS]