(a+b)^2x^2-4abx-(a-b)^2=0

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Q. Solve the following quadratic equations by factorization:

{(a + b)}^{2} x^{2} - 4 a b x - {(a - b)}^{2} = 0

Q. Solve the following quadratic equation by factorization :

(a + b)^{2} x^{2} - 4 a b x - (a - b)^{2} = 0

The roots are 1,

- {(\frac{a - b}{a + b})}^{2}

Q. If the roots of

(a^{2} + b^{2}) x^{2} - 2 b (a + c) x + (b^{2} + c^{2}) = 0

are equal then

a, b, c

are in

Q. If the roots of the equations

(a^{2} + b^{2}) x^{2} - 2 b (a + c) x + (b^{2} + c^{2}) = 0

are equal, then

(a) 2b = a + c
(b) b² = ac
(c)

b = \frac{2 a c}{a + c}

(d) b = ac

If α and β be the roots of the equation $2 x^{2} + 2 (a + b) x + a^{2} + b^{2} = 0$ , then the equation whose roots are $(α + β)^{2}$ and $(α - β)^{2})$ is

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