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Question

(a+b)3=a3+3xab+3ab2+b2y.Then x+y is always


A

a multiple of (a+b)

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B

a multiple of ab

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C

a prime number

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D

an even number

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Solution

The correct option is A

a multiple of (a+b)


(a+b)3=a3+3a2b+3ab2+b3
Comparing with the given expansion
x=a
y=b
(x+y)=(a+b)
So, we can say that (x +y) is a multiple of (a +b).

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