(a+b)3−(a−b)3 =________
b3+3a2b
2(b3+3a2b)
2(a3+3ab2)
0
(a+b)3−(a−b)3 =(a3+b3+3a2b+3ab2)-(a3−b3−3a2b+3ab2) =a3+b3+3a2b+3ab2−a3+b3+3a2b−3ab2 =2(b3+3a2b)