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A, B and C are three complexes of chromium (III) with the empirical formula H12O6Cl3Cr. All the three complexes have water and chloride ions as ligands. Complex A does not react with concentrated H2SO4, whereas complexes B and C lose 6.75% and 13.5% of their original weight respectively, on treatment with concentrated H2SO4.

Thus, select the correct statement :

A
Conductance in these complexes is in order C < B < A.
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B
EAN and nuclear spin of chromium are identical in each complex.
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C
Non-reactivity of A with conc. H2SO4 is due to absence of water molecules outside coordinated sphere.
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D
All of the above are correct.
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Solution

The correct option is D All of the above are correct.
(A) The molar mass of H12O6Cl3Cr is 266.5 g/mol. 6.75% of it corresponds to 18 g or 1 water molecule and 13.5% of it corresponds to 36 g or 2 water molecules. These water molecules are present in the ionization sphere.

Compounds A, B and C are represented by the formulae [Cr(H2O)6]Cl3, [Cr(H2O)5Cl]Cl2H2O and [Cr(H2O)4Cl2]Cl(H2O)2, respectively.

Conductance in these complexes is in order C < B < A. This is the same order in which the charge on the complex ion and the number of chloride ions in the ionization sphere increases.

Hence, the option A is correct.

(B) EAN and nuclear spin of chromium are identical in each complex.
This is because, the total number of primary and secondary valencies are same in these complexes.

Hence, the option B is correct.

(C) Sulphuric acid is strong dehydrating agent. It removes water molecule from ionization sphere but not from coordination sphere.

In the compound A, represented by formula [Cr(H2O)6]Cl3, no water molecule is present in the ionization sphere.

Hence, no reaction occurs with sulphuric acid. Hence, the option C is correct.

Therefore, correct option is D.

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