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Question

A, B and C are three points on a circle, then the perpendicular bisector of AB, BC and CA are ____________.

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Solution

Given:
A, B and C are three points on a circle


Let ABC be a triangle.
We know, a circumcentre is the point of intersection of the perpendicular bisectors of the triangle.

Thus, the perpendicular bisector of AB, BC and CA intersect at a point known as circumcentre.

Hence, the perpendicular bisector of AB, BC and CA are concurrent.

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