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Question

A. B and C are three tuning forks. Frequency of A is 350Hz. Beats produced by A and B are 5 per second and by B and C are 4 per second. When a wax is put on A beat frequency between A and B is 2Hz and between A and C is 6Hz. Then, find the frequency of B and C respectively.

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Solution

answer:fb=345Hz,fc=341 or 349Hz
fa=350
|fafb|=5
|fbfc|=4
since on adding wax frequency of A reduced , the difference between frequency of A and B also reduced this means frequency A >frequency B
now ,
fafb=5
350fb=5
fb=345

if fb>fc
fbfc=4
fc=341Hz

if fb<fc
fcfb=4
fc=349Hz

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