A,B and C gases taken in a volume ratio of 3:2:4 contains atoms in the ratio of 1:2:8/3. The gases having minimum and maximum atomicity are respectively:
A
C and B
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B
A and C
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C
A and B
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D
B and C have same atomicity
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Solution
The correct option is DA and B Ratio of volumes for gases A:B:C=3:2:4
Since, volume of a gas is directly proportional to moles at a given set of conditions, ratio of moles of gases =3:2:4
Ratio of atoms =1:2:8/3
3moles of gas A contain atoms =x
1molecule of gas has atoms =x3NA
Atomicity =x3NA
2moles of gas B contain atoms =2x
1molecule of gas has atoms =2x2NA
Atomicity =xNA
4moles of gas C contain atoms =83x
1molecule of gas has atoms =8x34NA
Atomicity =2x3NA
Therefore gas A has minimum atomicity while gas B has maximum atomicity.