wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

A,B and C gases taken in a volume ratio of 3:2:4 contains atoms in the ratio of 1:2:8/3. The gases having minimum and maximum atomicity are respectively:

A
C and B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
A and C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A and B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
B and C have same atomicity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D A and B
Ratio of volumes for gases A:B:C=3:2:4
Since, volume of a gas is directly proportional to moles at a given set of conditions, ratio of moles of gases =3:2:4
Ratio of atoms =1:2:8/3
3 moles of gas A contain atoms =x
1 molecule of gas has atoms =x3NA
Atomicity =x3NA

2 moles of gas B contain atoms =2x
1 molecule of gas has atoms =2x2NA
Atomicity =xNA

4 moles of gas C contain atoms =83x
1 molecule of gas has atoms =8x34NA
Atomicity =2x3NA

Therefore gas A has minimum atomicity while gas B has maximum atomicity.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ideal Gas Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon