A, B and C working together can finish a piece of work in 8 hours. A alone can do it in 20 hours and B alone can do It in 24 hours. In how many hours will C atone do the salve work?

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Solution

A,B and C's 1 hour's work $= \frac{1}{8}$

A's 1 hour's work $= \frac{1}{20}$

B's 1 hour's work $= \frac{1}{24}$

$∴$ C's 1 hours work $= \frac{1}{8} - (\frac{1}{20} + \frac{1}{24})$

$= \frac{15 - (6 + 5)}{120} = \frac{15 - 11}{120}$

$= \frac{4}{120} = \frac{1}{30}$

$∴$ C alone finish the work in =30 hours.

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A, B and C working together can finish a piece of work in 8 hours. A alone can do it in 20 hours and B alone can do It in 24 hours. In how many hours will C atone do the salve work?

A,B and C's 1 hour's work =18 A's 1 hour's work =120 B's 1 hour's work =124 ∴ C's 1 hours work =18−(120+124) =15−(6+5)120=15−11120 =4120=130 ∴ C alone finish the work in =30 hours.