A & B are two fixed points. The vertex C of △ABC moves such that cotA+cotB= constant. The locus of C is a straight line
A
⊥er to AB
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B
parallel to AB
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C
inclined to an angle to AB
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D
None of these
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Solution
The correct option is B parallel to AB We have cotA=ADCD,cotB=DBCD Now cotA=+cotB=AD+DBCD ⇒ Constant(given) =ABCD ⇒CD= constant (As A,B are fixed points so AB is a constant) ⇒ locus of C is a straight line parallel to AB Hence choice (b) is correct answer.