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Question

A & B are two fixed points. The vertex C of ABC moves such that cotA+cotB= constant. The locus of C is a straight line

A
er to AB
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B
parallel to AB
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C
inclined to an angle to AB
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D
None of these
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Solution

The correct option is B parallel to AB
We have cotA=ADCD,cotB=DBCD
Now cotA=+cotB=AD+DBCD
Constant(given) =ABCD
CD= constant
(As A,B are fixed points so AB is a constant)
locus of C is a straight line parallel to AB
Hence choice (b) is correct answer.
239041_165097_ans.PNG

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