$a, b, c (a > c)$ are three digits from left to right, of a three digits number. If the number with these digits reversed is subtracted from the original number, the resulting number has the digits 4 in its unit place. The other two digits from left to right are

5 and 4

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5 and 9

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4 and 5

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9 and 5

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Solution

The correct option is C 5 and 9
$L e t t h e n u m b e r b e w r i t t e n a s f o l l o w s P l a c e v a l u e ⟶ H u n d r e d s T e n s U n i t s a b c R e v e r s i n g ⟶ c b a U n i t s p l a c e : - G i v e n a > c ∴ W e b o r r o w 10 a n d t h e r e s u l t i s c + 10 - a = 4 \Rightarrow a = c + 6 - - - - (1) T e n s p l a c e : - u p p e r r o w b h a s b e c o m e b - 1 ∴ W e b o r r o w 10 a n d t h e r e s u l t i s (b - 1 + 10) - b = 9. H u n d r e d s p l a c e : - a h a s b e c o m e a - 1 ∴ (a - 1) - c i s t h e r e s u l t . S u b s t i t u t i n g t h e v a l u e o f a f r o m (1), t h e r e s u l t w i l l b e c + 6 - 1 - c = 5 ∴ T h e o t h e r t w o n u m b e r s a r e 5, 9 (A n s) (i . e . T h e r e s u l t i s 594)$

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