Question

A, B, C, and D are 4 non-equal digits. Find ${\mathrm{AC}}^2$ if, B>A & AC*BC = DDD.

• A. 729
• B. 676
• C. 625
• D. 576

Answer 1

The correct option is A 729

If you observe the options, all of them are perfect squares whose roots are, 27,26,25 and 24.
Consider option (a), 729. Root of 729 = 27, where A = 2, C=7.
As per the condition B>A, so let B=3.
Thus, AC*BC=27*37=999. Thus, option (a) will be the required solution.