$A, B, C$ and $D$ are four point on a circle. How many chords can be drawn using only these points as the end points of the chord.

Open in App

Solution

By selecting $2$ points out of $4$ we can draw a chord $\Rightarrow$ Total chords $=^{4} C_{2} = \frac{4!}{2! 2!} = 6$
These chords would be AB, AC, AD, BC, BD, CD.

Suggest Corrections

Similar questions

Q. How many chords can be drawn through

21

points on a circle?

Q. Seven points lie on a circle. How many chords can be drawn by joining these points.

Q. Six points were chosen on a circle and every possible chord was drawn. Two chords, which do not have the common points are named separately. How many pairs of separate chords exist in the situation described above?

There are 5 equally spaced points A,B,C,D, E and F marked on a circle with radius R. How many convex hexagons of distinctly different areas can be drawn using these points as vertices?

P is a point inside a circle centered at O which does not coincide with the point O. How many chords can be drawn with P as the mid-point?

Join BYJU'S Learning Program

A,B,C and D are four point on a circle. How many chords can be drawn using only these points as the end points of the chord.

By selecting 2 points out of 4 we can draw a chord ⇒ Total chords =4C2=4!2!2!=6These chords would be AB, AC, AD, BC, BD, CD.

$A, B, C$ and $D$ are four point on a circle. How many chords can be drawn using only these points as the end points of the chord.

By selecting $2$ points out of $4$ we can draw a chord $\Rightarrow$ Total chords $=^{4} C_{2} = \frac{4!}{2! 2!} = 6$
These chords would be AB, AC, AD, BC, BD, CD.