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Question

A, B, C and D are points in a vertical line such that AB = BC = CD. If a body falls from rest from A, then the times of descend through AB, BC and CD are in ratio:-

A
1:2:3
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B
2:3 : 1
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C
3:1:2
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D
1:(21):(32)
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Solution

The correct option is C 1:(21):(32)
In above figure,
A body released u=0
Let h1=12gt21
t1=2hg×1...(1)
t1+t2=2(2h)g
t2=2hg×(21)...(2)
Now, t1+t2+t3=2(3h)g
t3=6hg4hg
t3=2hg×(32)...(3)
From (1),(2) and (3), we get
t1:t2:t3=1:(21):(32)
Hence, D is correct option.

1932737_1432344_ans_c2a66b165cc84895a5301a8990d6cd9c.png

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