Question

A, B, C are any points on the circle with centre O. m(arc BC)=120${}^{\circ }$ and m(arc AB)=130${}^{\circ }.$
Then,

• A. ${250}^{\circ }$
• B. ${110}^{\circ }$
• C. ${230}^{\circ }$
• D. ${240}^{\circ }$

Answer 1

By property of sum of measure of arcs, we must have
m(arc ABC) = m(arc AB) + m(arc BC)
$⟹$ m(arc ABC) = 130${}^{\circ }$ + 120${}^{\circ }$
= 250${}^{\circ }$
m(arc AC) = 360${}^{\circ }$ - m(arc ABC)
$⟹$ m(arc AC) = 360${}^{\circ }$ - 250${}^{\circ }$
= 110${}^{\circ }$
m(arc ACB) = m(arc AC) + m(arc BC)
$⟹$ m(arc ACB) = 110${}^{\circ }$ + 120${}^{\circ }$
= 230${}^{\circ }$
m(arc BAC) = 360${}^{\circ }$ - m(arc BC)
$⟹$ m(arc AC) = 360${}^{\circ }$ - 120${}^{\circ }$
= 240${}^{\circ }$