A-B-C are cofactors of elements- a- b- c in - a b c- 2 4 7- -1 0 3 - then the value of 2A-4B-7Cis equal to

The correct option is A 0 A = 4× 3 0× 7 = 12 B = (2× 3 7× ( 1)) = 13 C = 2× 0 4× ( 1) = 4 2A+4B+7C = 0 ...

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Cofactor

A,B,C are cof...

Question

$A, B, C$ are cofactors of elements, $a, b, c$ in

$⎡ ⎢ ⎣ \begin{matrix} a & b & c 2 & 4 & 7 - 1 & 0 & 3 \end{matrix} ⎤ ⎥ ⎦$ then the value of $(2 A + 4 B + 7 C)$
is equal to

0

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Similar questions

A_{1}, B_{1}, C_{1}, . . . .

a_{1}, b_{1}, c_{1}, . . . .

Δ = ∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣, Δ \neq 0

∣ ∣ ∣ \begin{matrix} B_{2} & C_{2} B_{3} & C_{3} \end{matrix} ∣ ∣ ∣

A_{1}, B_{1}, C_{1}, . .

a_{1}, b_{1}, c_{1}, . .

Δ = ∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣

Δ \neq 0

∣ ∣ ∣ \begin{matrix} B_{2} & C_{2} B_{3} & C_{3} \end{matrix} ∣ ∣ ∣

A B C, 2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c,

cos B

A B C

2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c

cos B

△ A B C, 2 a^{2} + 4 b^{2} + c^{2} = 4 a b + 2 a c

cos B

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