a, b, c are in continued proportion and if $a = 6$ and $c = 24$ then find 'b'.

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Solution

$a, b, c$ are in continued proportion. Therefore,
$\frac{a}{b} = \frac{b}{c}$

$\frac{6}{b} = \frac{b}{24}$

$b^{2} = 24 \times 6 = 144$
$⟹ b = 12$

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