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Question

A,B,C are interior angles of ABC. then that is csc(A+B2)=secC2 true/ false ?

A
True
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B
False
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Solution

The correct option is A True
Given

In ΔABC

A+B+C=π

A+B=πC

A+B2=π2C2

Applying Cosecant on both sides

csc(A+B2)=csc(π2C2)

csc(A+B2)=sec(C2)


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