a, b, c are positive integers forming an increasing G.P. whose common ratio is a natural number, b – a is a cube of natural number and $l o g_{6} a + l o g_{6} b + l o g_{6} c = 6$ , then a + b + c is divisible by

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A 3
C 7
$l o g_{6} a b c = 6$
$a b c = 6^{6} \Rightarrow b^{3} = 6^{6}$
b - a is cube of a natural number
b = 36, a = 9, c = 144
a + b + c = 189
which is divisible by 3 and 7

Suggest Corrections

Similar questions

log (\frac{5 c}{a}) log (\frac{3 b}{5 c})

log (\frac{a}{3 b})

a, b, c

l o g (\frac{5 c}{a}), l o g (\frac{3 b}{5 c}), l o g (\frac{a}{3 b})

a, b, c

If $p = 2^{a} \times 3^{b} \times 5^{c}$ and $a > b > c$ are natural numbers, then what is the unit digit of $p$ ?

If $p = 2^{a} \times 3^{b} \times 5^{c}$ and $a > b > c$ are natural numbers, then what is the unit digit of p?

n^{2} - 1

Join BYJU'S Learning Program