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Question

A,B,C are three angles such that tanA+tanB+tanC=tanAtanBtanC. Which of the following statements is always correct ?

A
ABC is a triangle, i.e. A+B+C=π
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B
A=B=C.i.e., ABC is an equilateral triangle
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C
A+B=C, i.e., ABC is a right- angled triangle
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D
A+B=π
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Solution

The correct option is A ABC is a triangle, i.e. A+B+C=π
(A) tan[(A+B)+C]
=tan(A+B)+tanC1tan(A+B)tanC=tanA+tanB1tanAtanB+tanC1tanA+tanB1tanAtanB.tanC
=tanA+tanB+tanCtanAtanBtanCDenominator
=0
[since,tanA+tanB+tanC=tanAtanBtanC]
A+B+C=π i.e., A, B, C is a triangle

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