The correct option is A ABC is a triangle, i.e. A+B+C=π
(A) tan[(A+B)+C]
=tan(A+B)+tanC1−tan(A+B)tanC=tanA+tanB1−tanAtanB+tanC1−tanA+tanB1−tanAtanB.tanC
=tanA+tanB+tanC−tanAtanBtanCDenominator
=0
[since,tanA+tanB+tanC=tanAtanBtanC]
∴A+B+C=π i.e., A, B, C is a triangle