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Question

A, B, C are three horses in a race. The probability of A to win the race is twice that of B and probability of B is twice that of C. What are the probabilities of A, B and C to win the race?

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Solution

Let the probability of A,B,C winning are a,b,c respectively
Then a+b+c=1
In question given a=2b
b=2c
Hence c=b2
So a+b+c=1
2b+b+b2=1
7b2=1
b=27
a=2b=47
c=b2=17
So PA=a=47
PB=b=27
PC=c=17

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