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Question

A, B, C are three horses in a race. The probability of A to win the race is twice that of B and probability of B is twice that of C. What are the probabilities of A, B and C to win the race?

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Solution

Let the probability of A,B,C winning are a,b,c respectively

Then a+b+c=1

In question given a=2b

b=2c

Hence c=b2

So a+b+c=1

2b+b+b2=1

7b2=1

b=27

a=2b=47

c=b2=17

So PA=a=47

PB=b=27

PC=c=17

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