A,B,C are three points on the axes of x,y and z respectively at distance a,b,c from the origin O; then the co - ordinates of the point which is equidistant from A,B,C and O is
A
(a,b,c)
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B
(a2,b2,c2)
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C
(a3,b3,c3)
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D
None of these
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Solution
The correct option is A(a2,b2,c2) Let P be the required point (x,y,z) and the point A,B,C and O are (a,0,0),(0,b,0),(0,0,c) and (0,0,0) ;
We are given that PO=PA=PB=PC. Taking PO=PA or PO2=PA2, we get x2+y2+z2=(x−a)2+y2+z2 0=a2−2ax i.e. x=a2 Similarly taking PO2=PB2 and PO2=PC2, we get