A,B,C are three points on the curve xy - x - y - 3 = 0 which are not collinear. D,E,F are foot of perpendiculars from vertices A,B,C to the sides BC,CA and AB of △ABC respectively. If (α,α\) is incentre of △DEF then 'α' can be
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is C 3 Incentre of △DEF is ortho-centre of △ABC. But in a rectangular hyperbola & ortho-centre lies on hyperbola ⇒α2−2α−3=0⇒(α−3)(α+1)=0⇒α=3